S(t)=5t2+100

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Solution for S(t)=5t2+100 equation: 



(S)=5S^2+100

We move all terms to the left:

(S)-(5S^2+100)=0

We get rid of parentheses

-5S^2+S-100=0

a = -5; b = 1; c = -100;
Δ = b2-4ac
Δ = 12-4·(-5)·(-100)
Δ = -1999
Delta is less than zero, so there is no solution for the equation

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