S(x+12)+x=3(4x-3)+1

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Solution for S(x+12)+x=3(4x-3)+1 equation: 



(S+12)+S=3(4S-3)+1

We move all terms to the left:

(S+12)+S-(3(4S-3)+1)=0

We add all the numbers together, and all the variables

S+(S+12)-(3(4S-3)+1)=0

We get rid of parentheses

S+S-(3(4S-3)+1)+12=0



We calculate terms in parentheses: -(3(4S-3)+1), so:

3(4S-3)+1

We multiply parentheses

12S-9+1

We add all the numbers together, and all the variables

12S-8

Back to the equation:

-(12S-8)



We add all the numbers together, and all the variables

2S-(12S-8)+12=0

We get rid of parentheses

2S-12S+8+12=0

We add all the numbers together, and all the variables

-10S+20=0

We move all terms containing S to the left, all other terms to the right

-10S=-20

S=-20/-10

S=+2

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