S+2+2(s+2)-2=20

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Solution for S+2+2(s+2)-2=20 equation: 



+2+2(S+2)-2=20

We move all terms to the left:

+2+2(S+2)-2-(20)=0

We add all the numbers together, and all the variables

2(S+2)-20=0

We multiply parentheses

2S+4-20=0

We add all the numbers together, and all the variables

2S-16=0

We move all terms containing S to the left, all other terms to the right

2S=16

S=16/2

S=8

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