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=1/5(300-5S)
We move all terms to the left:
-(1/5(300-5S))=0
Domain of the equation: 5(300-5S))!=0We add all the numbers together, and all the variables
S∈R
-(1/5(-5S+300))=0
We multiply all the terms by the denominator
-(1=0
We add all the numbers together, and all the variables
=0
S=0/1
S=0
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