If it's not what You are looking for type in the equation solver your own equation and let us solve it.
=19S^2
We move all terms to the left:
-(19S^2)=0
a = -19; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-19)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$S=\frac{-b}{2a}=\frac{0}{-38}=0$
| [2d-3[=19 | | -2x^2+12^2-10=0 | | -2p+21=11 | | 3.652-a;a=1.41 | | 3x-9=8-4 | | 0=6x^-96 | | 4^(5x-7)=3^(9x-6) | | 4(m-8)=-4 | | R+15.9;r=0.214 | | `(3x+5)(3x-5)=(9x-25)` | | 5x^2—2x=16 | | 24.84-h;h=22.7 | | 5│7x+6│=40 | | 7x+6=457x+6=-45 | | (2x-5)(2x-15)=4x^2+5x | | -12/2+m=2 | | G(x)=5x2-4x | | 14.2=2t | | -12+m/2=2 | | 180=126+22+x | | √5x2-5x+√5=0 | | (2x-5)(2x-15)=4x^2-5x | | 2-4m=50 | | 18x+7x=+3-5 | | 3/4x+2/4=0.25 | | 31=11-5m | | 18x-3=-7x-5 | | 31=11-m | | 5+7m=-9 | | ✓5x2-5x+✓5=0 | | -7+m/5=-10 | | -11-m=-17 |