S=2(s+3)+4s-5

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Solution for S=2(s+3)+4s-5 equation: 



=2(S+3)+4S-5

We move all terms to the left:

-(2(S+3)+4S-5)=0



We calculate terms in parentheses: -(2(S+3)+4S-5), so:

2(S+3)+4S-5

We add all the numbers together, and all the variables

4S+2(S+3)-5

We multiply parentheses

4S+2S+6-5

We add all the numbers together, and all the variables

6S+1

Back to the equation:

-(6S+1)



We get rid of parentheses

-6S-1=0

We move all terms containing S to the left, all other terms to the right

-6S=1

S=1/-6

S=-1/6

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