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=328.27S-0.03S^2
We move all terms to the left:
-(328.27S-0.03S^2)=0
We get rid of parentheses
0.03S^2-328.27S=0
a = 0.03; b = -328.27; c = 0;
Δ = b2-4ac
Δ = -328.272-4·0.03·0
Δ = 107761.1929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$S_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$S_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$S_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-328.27)-\sqrt{107761.1929}}{2*0.03}=\frac{328.27-\sqrt{107761.1929}}{0.06} $$S_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-328.27)+\sqrt{107761.1929}}{2*0.03}=\frac{328.27+\sqrt{107761.1929}}{0.06} $
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