S=n/2(a+1)

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Solution for S=n/2(a+1) equation: 


x in (-oo:+oo)

S = (n/2)*(a+1) // - (n/2)*(a+1)

S-((n/2)*(a+1)) = 0

S-1*1/2*n*(a+1) = 0

S-1*1/2*n*(a+1) = 0

S-1/2*a*n-1/2*n = 0

S-1/2*a*n-1/2*n = 0

x belongs to the empty set

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