Sin(2x-10)=cos(5x-40)

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Solution for Sin(2x-10)=cos(5x-40) equation: 


Simplifying
Sin(2x + -10) = cos(5x + -40)

Reorder the terms:
inS(-10 + 2x) = cos(5x + -40)
(-10 * inS + 2x * inS) = cos(5x + -40)
(-10inS + 2inxS) = cos(5x + -40)

Reorder the terms:
-10inS + 2inxS = cos(-40 + 5x)
-10inS + 2inxS = (-40 * cos + 5x * cos)
-10inS + 2inxS = (-40cos + 5cosx)

Solving
-10inS + 2inxS = -40cos + 5cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
40cos + -5cosx + -10inS + 2inxS = -40cos + 5cosx + 40cos + -5cosx

Reorder the terms:
40cos + -5cosx + -10inS + 2inxS = -40cos + 40cos + 5cosx + -5cosx

Combine like terms: -40cos + 40cos = 0
40cos + -5cosx + -10inS + 2inxS = 0 + 5cosx + -5cosx
40cos + -5cosx + -10inS + 2inxS = 5cosx + -5cosx

Combine like terms: 5cosx + -5cosx = 0
40cos + -5cosx + -10inS + 2inxS = 0

The solution to this equation could not be determined.

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