Sin(3x+1)=cos(4x-9)

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Solution for Sin(3x+1)=cos(4x-9) equation: 


Simplifying
Sin(3x + 1) = cos(4x + -9)

Reorder the terms:
inS(1 + 3x) = cos(4x + -9)
(1 * inS + 3x * inS) = cos(4x + -9)
(1inS + 3inxS) = cos(4x + -9)

Reorder the terms:
1inS + 3inxS = cos(-9 + 4x)
1inS + 3inxS = (-9 * cos + 4x * cos)
1inS + 3inxS = (-9cos + 4cosx)

Solving
1inS + 3inxS = -9cos + 4cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
9cos + -4cosx + 1inS + 3inxS = -9cos + 4cosx + 9cos + -4cosx

Reorder the terms:
9cos + -4cosx + 1inS + 3inxS = -9cos + 9cos + 4cosx + -4cosx

Combine like terms: -9cos + 9cos = 0
9cos + -4cosx + 1inS + 3inxS = 0 + 4cosx + -4cosx
9cos + -4cosx + 1inS + 3inxS = 4cosx + -4cosx

Combine like terms: 4cosx + -4cosx = 0
9cos + -4cosx + 1inS + 3inxS = 0

The solution to this equation could not be determined.

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