Sin(3x+2)=cos(4x+10)

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Solution for Sin(3x+2)=cos(4x+10) equation:


Simplifying
Sin(3x + 2) = cos(4x + 10)

Reorder the terms:
inS(2 + 3x) = cos(4x + 10)
(2 * inS + 3x * inS) = cos(4x + 10)
(2inS + 3inxS) = cos(4x + 10)

Reorder the terms:
2inS + 3inxS = cos(10 + 4x)
2inS + 3inxS = (10 * cos + 4x * cos)
2inS + 3inxS = (10cos + 4cosx)

Solving
2inS + 3inxS = 10cos + 4cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
-10cos + -4cosx + 2inS + 3inxS = 10cos + 4cosx + -10cos + -4cosx

Reorder the terms:
-10cos + -4cosx + 2inS + 3inxS = 10cos + -10cos + 4cosx + -4cosx

Combine like terms: 10cos + -10cos = 0
-10cos + -4cosx + 2inS + 3inxS = 0 + 4cosx + -4cosx
-10cos + -4cosx + 2inS + 3inxS = 4cosx + -4cosx

Combine like terms: 4cosx + -4cosx = 0
-10cos + -4cosx + 2inS + 3inxS = 0

The solution to this equation could not be determined.

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