Sin(3x-10)=cos(2x+10)

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Solution for Sin(3x-10)=cos(2x+10) equation:


Simplifying
Sin(3x + -10) = cos(2x + 10)

Reorder the terms:
inS(-10 + 3x) = cos(2x + 10)
(-10 * inS + 3x * inS) = cos(2x + 10)
(-10inS + 3inxS) = cos(2x + 10)

Reorder the terms:
-10inS + 3inxS = cos(10 + 2x)
-10inS + 3inxS = (10 * cos + 2x * cos)
-10inS + 3inxS = (10cos + 2cosx)

Solving
-10inS + 3inxS = 10cos + 2cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
-10cos + -2cosx + -10inS + 3inxS = 10cos + 2cosx + -10cos + -2cosx

Reorder the terms:
-10cos + -2cosx + -10inS + 3inxS = 10cos + -10cos + 2cosx + -2cosx

Combine like terms: 10cos + -10cos = 0
-10cos + -2cosx + -10inS + 3inxS = 0 + 2cosx + -2cosx
-10cos + -2cosx + -10inS + 3inxS = 2cosx + -2cosx

Combine like terms: 2cosx + -2cosx = 0
-10cos + -2cosx + -10inS + 3inxS = 0

The solution to this equation could not be determined.

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