Sin(3x-50)=Cos(20-2x)

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Solution for Sin(3x-50)=Cos(20-2x) equation: 


Simplifying
Sin(3x + -50) = Cos(20 + -2x)

Reorder the terms:
inS(-50 + 3x) = Cos(20 + -2x)
(-50 * inS + 3x * inS) = Cos(20 + -2x)
(-50inS + 3inxS) = Cos(20 + -2x)
-50inS + 3inxS = (20 * osC + -2x * osC)
-50inS + 3inxS = (20osC + -2osxC)

Solving
-50inS + 3inxS = 20osC + -2osxC

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
-50inS + 3inxS + -20osC + 2osxC = 20osC + -20osC + -2osxC + 2osxC

Combine like terms: 20osC + -20osC = 0
-50inS + 3inxS + -20osC + 2osxC = 0 + -2osxC + 2osxC
-50inS + 3inxS + -20osC + 2osxC = -2osxC + 2osxC

Combine like terms: -2osxC + 2osxC = 0
-50inS + 3inxS + -20osC + 2osxC = 0

The solution to this equation could not be determined.

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