Sin(4x+7)=cos(2x-13)

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Solution for Sin(4x+7)=cos(2x-13) equation:


Simplifying
Sin(4x + 7) = cos(2x + -13)

Reorder the terms:
inS(7 + 4x) = cos(2x + -13)
(7 * inS + 4x * inS) = cos(2x + -13)
(7inS + 4inxS) = cos(2x + -13)

Reorder the terms:
7inS + 4inxS = cos(-13 + 2x)
7inS + 4inxS = (-13 * cos + 2x * cos)
7inS + 4inxS = (-13cos + 2cosx)

Solving
7inS + 4inxS = -13cos + 2cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
13cos + -2cosx + 7inS + 4inxS = -13cos + 2cosx + 13cos + -2cosx

Reorder the terms:
13cos + -2cosx + 7inS + 4inxS = -13cos + 13cos + 2cosx + -2cosx

Combine like terms: -13cos + 13cos = 0
13cos + -2cosx + 7inS + 4inxS = 0 + 2cosx + -2cosx
13cos + -2cosx + 7inS + 4inxS = 2cosx + -2cosx

Combine like terms: 2cosx + -2cosx = 0
13cos + -2cosx + 7inS + 4inxS = 0

The solution to this equation could not be determined.

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