Sin(7x+15)=cos(3x+40)

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Solution for Sin(7x+15)=cos(3x+40) equation:


Simplifying
Sin(7x + 15) = cos(3x + 40)

Reorder the terms:
inS(15 + 7x) = cos(3x + 40)
(15 * inS + 7x * inS) = cos(3x + 40)
(15inS + 7inxS) = cos(3x + 40)

Reorder the terms:
15inS + 7inxS = cos(40 + 3x)
15inS + 7inxS = (40 * cos + 3x * cos)
15inS + 7inxS = (40cos + 3cosx)

Solving
15inS + 7inxS = 40cos + 3cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
-40cos + -3cosx + 15inS + 7inxS = 40cos + 3cosx + -40cos + -3cosx

Reorder the terms:
-40cos + -3cosx + 15inS + 7inxS = 40cos + -40cos + 3cosx + -3cosx

Combine like terms: 40cos + -40cos = 0
-40cos + -3cosx + 15inS + 7inxS = 0 + 3cosx + -3cosx
-40cos + -3cosx + 15inS + 7inxS = 3cosx + -3cosx

Combine like terms: 3cosx + -3cosx = 0
-40cos + -3cosx + 15inS + 7inxS = 0

The solution to this equation could not be determined.

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