Sin(pi/3-5x)=2.sinx - solution

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Solution for Sin(pi/3-5x)=2.sinx equation:

Oblicz to!

x = 10

T/6-5 = 13

(-x)^3+8*x^2-(19*x)+12 = 0

(x^2-x+1)/(x^2+x+1)

y = -((8/7)*x)

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