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x in (-oo:+oo)
sin(pi/3-x) = 0
sin(pi/3-x) = 0 <=> pi/3-x = pi*k_1 i k_1 należy do I
t_1 = pi*k_1
pi/3-t_1-x = 0
pi/3-t_1-x = 0 // - pi/3-t_1
-x = -(pi/3-t_1) // * -1
x = pi/3-t_1
x = pi*k_1+pi/3 i k_1 należy do I
x = pi*k_1+pi/3
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