T(2)=35x2+20

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Solution for T(2)=35x2+20 equation: 



(2)=35T^2+20

We move all terms to the left:

(2)-(35T^2+20)=0

We get rid of parentheses

-35T^2-20+2=0

We add all the numbers together, and all the variables

-35T^2-18=0

a = -35; b = 0; c = -18;
Δ = b2-4ac
Δ = 02-4·(-35)·(-18)
Δ = -2520
Delta is less than zero, so there is no solution for the equation

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