T(2t+5)-5(1-2t)=2(3+4t)-3(t-4)

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Solution for T(2t+5)-5(1-2t)=2(3+4t)-3(t-4) equation: 



(2T+5)-5(1-2T)=2(3+4T)-3(T-4)

We move all terms to the left:

(2T+5)-5(1-2T)-(2(3+4T)-3(T-4))=0

We add all the numbers together, and all the variables

(2T+5)-5(-2T+1)-(2(4T+3)-3(T-4))=0

We multiply parentheses

(2T+5)+10T-(2(4T+3)-3(T-4))-5=0

We get rid of parentheses

2T+10T-(2(4T+3)-3(T-4))+5-5=0



We calculate terms in parentheses: -(2(4T+3)-3(T-4)), so:

2(4T+3)-3(T-4)

We multiply parentheses

8T-3T+6+12

We add all the numbers together, and all the variables

5T+18

Back to the equation:

-(5T+18)



We add all the numbers together, and all the variables

12T-(5T+18)=0

We get rid of parentheses

12T-5T-18=0

We add all the numbers together, and all the variables

7T-18=0

We move all terms containing T to the left, all other terms to the right

7T=18

T=18/7

T=2+4/7

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