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(2T+5)-5(1-2T)=2(3+4T)-3(T-4)
We move all terms to the left:
(2T+5)-5(1-2T)-(2(3+4T)-3(T-4))=0
We add all the numbers together, and all the variables
(2T+5)-5(-2T+1)-(2(4T+3)-3(T-4))=0
We multiply parentheses
(2T+5)+10T-(2(4T+3)-3(T-4))-5=0
We get rid of parentheses
2T+10T-(2(4T+3)-3(T-4))+5-5=0
We calculate terms in parentheses: -(2(4T+3)-3(T-4)), so:We add all the numbers together, and all the variables
2(4T+3)-3(T-4)
We multiply parentheses
8T-3T+6+12
We add all the numbers together, and all the variables
5T+18
Back to the equation:
-(5T+18)
12T-(5T+18)=0
We get rid of parentheses
12T-5T-18=0
We add all the numbers together, and all the variables
7T-18=0
We move all terms containing T to the left, all other terms to the right
7T=18
T=18/7
T=2+4/7
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