T-(2t+5)-5(1-2t)=2(3+4t)-3(t-5)

Solution for T-(2t+5)-5(1-2t)=2(3+4t)-3(t-5) equation:

-(2T+5)-5(1-2T)=2(3+4T)-3(T-5)

We move all terms to the left:

-(2T+5)-5(1-2T)-(2(3+4T)-3(T-5))=0

We add all the numbers together, and all the variables

-(2T+5)-5(-2T+1)-(2(4T+3)-3(T-5))=0

We multiply parentheses

-(2T+5)+10T-(2(4T+3)-3(T-5))-5=0

We get rid of parentheses

-2T+10T-(2(4T+3)-3(T-5))-5-5=0


We calculate terms in parentheses: -(2(4T+3)-3(T-5)), so:

2(4T+3)-3(T-5)

We multiply parentheses

8T-3T+6+15

We add all the numbers together, and all the variables

5T+21

Back to the equation:

-(5T+21)


We add all the numbers together, and all the variables

8T-(5T+21)-10=0

We get rid of parentheses

8T-5T-21-10=0

We add all the numbers together, and all the variables

3T-31=0

We move all terms containing T to the left, all other terms to the right

3T=31

T=31/3

T=10+1/3