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/9+2(T/9+4)=10
We move all terms to the left:
/9+2(T/9+4)-(10)=0
determiningTheFunctionDomain 2(T/9+4)-10+/9=0
We multiply parentheses
2T+8-10+/9=0
We multiply all the terms by the denominator
2T*9+8*9-10*9+=0
We add all the numbers together, and all the variables
2T*9=0
Wy multiply elements
18T=0
T=0/18
T=0
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