T=4+(n-1)(12)

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Solution for T=4+(n-1)(12) equation: 



=4+(T-1)(12)

We move all terms to the left:

-(4+(T-1)(12))=0



We calculate terms in parentheses: -(4+(T-1)12), so:

4+(T-1)12

determiningTheFunctionDomain
(T-1)12+4

We multiply parentheses

12T-12+4

We add all the numbers together, and all the variables

12T-8

Back to the equation:

-(12T-8)



We get rid of parentheses

-12T+8=0

We move all terms containing T to the left, all other terms to the right

-12T=-8

T=-8/-12

T=2/3

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