Tn=25*(1/5)n-1

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Solution for Tn=25*(1/5)n-1 equation: 



T=25(1/5)T-1

We move all terms to the left:

T-(25(1/5)T-1)=0



Domain of the equation: 5)T-1)!=0

T!=0/1

T!=0

T∈R



We add all the numbers together, and all the variables

T-(25(+1/5)T-1)=0

We multiply all the terms by the denominator


T*5)T-1)-(25(+1=0

Wy multiply elements

5T^2+1=0

a = 5; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·5·1
Δ = -20
Delta is less than zero, so there is no solution for the equation

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