Tn=n2+3n+4

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Solution for Tn=n2+3n+4 equation:



T=T2+3T+4
We move all terms to the left:
T-(T2+3T+4)=0
We add all the numbers together, and all the variables
-(+T^2+3T+4)+T=0
We get rid of parentheses
-T^2-3T+T-4=0
We add all the numbers together, and all the variables
-1T^2-2T-4=0
a = -1; b = -2; c = -4;
Δ = b2-4ac
Δ = -22-4·(-1)·(-4)
Δ = -12
Delta is less than zero, so there is no solution for the equation

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