V(t)=120t/4t-2

Solution for V(t)=120t/4t-2 equation:

(V)=120V/4V-2

We move all terms to the left:

(V)-(120V/4V-2)=0


Domain of the equation: 4V-2)!=0

V∈R


We get rid of parentheses

V-120V/4V+2=0

We multiply all the terms by the denominator


V*4V-120V+2*4V=0

We add all the numbers together, and all the variables

-120V+V*4V+2*4V=0

Wy multiply elements

4V^2-120V+8V=0

We add all the numbers together, and all the variables

4V^2-112V=0

a = 4; b = -112; c = 0;
Δ = b2-4ac
Δ = -1122-4·4·0
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-112)-112}{2*4}=\frac{0}{8}
=0
$
$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-112)+112}{2*4}=\frac{224}{8}
=28
$