V(t)=2t2-16t+40

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Solution for V(t)=2t2-16t+40 equation: 



(V)=2V^2-16V+40

We move all terms to the left:

(V)-(2V^2-16V+40)=0

We get rid of parentheses

-2V^2+V+16V-40=0

We add all the numbers together, and all the variables

-2V^2+17V-40=0

a = -2; b = 17; c = -40;
Δ = b2-4ac
Δ = 172-4·(-2)·(-40)
Δ = -31
Delta is less than zero, so there is no solution for the equation

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