V(x)=12/2x-5

Solution for V(x)=12/2x-5 equation:

(V)=12/2V-5

We move all terms to the left:

(V)-(12/2V-5)=0


Domain of the equation: 2V-5)!=0

V∈R


We get rid of parentheses

V-12/2V+5=0

We multiply all the terms by the denominator


V*2V+5*2V-12=0

Wy multiply elements

2V^2+10V-12=0

a = 2; b = 10; c = -12;
Δ = b2-4ac
Δ = 102-4·2·(-12)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-14}{2*2}=\frac{-24}{4}
=-6
$
$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+14}{2*2}=\frac{4}{4}
=1
$