V(x)=x(3-2x)(5-2x)

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Solution for V(x)=x(3-2x)(5-2x) equation: 



(V)=V(3-2V)(5-2V)

We move all terms to the left:

(V)-(V(3-2V)(5-2V))=0

We add all the numbers together, and all the variables

V-(V(-2V+3)(-2V+5))=0

We multiply parentheses ..

-(V(+4V^2-10V-6V+15))+V=0



We calculate terms in parentheses: -(V(+4V^2-10V-6V+15)), so:

V(+4V^2-10V-6V+15)

We multiply parentheses

4V^3-10V^2-6V^2+15V

We do not support eVpression: V^3

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