V-1-6v=2(v+4)-3(8v+3)

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Solution for V-1-6v=2(v+4)-3(8v+3) equation: 



-1-6V=2(V+4)-3(8V+3)

We move all terms to the left:

-1-6V-(2(V+4)-3(8V+3))=0



We calculate terms in parentheses: -(2(V+4)-3(8V+3)), so:

2(V+4)-3(8V+3)

We multiply parentheses

2V-24V+8-9

We add all the numbers together, and all the variables

-22V-1

Back to the equation:

-(-22V-1)



We get rid of parentheses

-6V+22V+1-1=0

We add all the numbers together, and all the variables

16V=0

V=0/16

V=0

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