V-2+3v=6(2v+4)-(v+5)

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Solution for V-2+3v=6(2v+4)-(v+5) equation: 



-2+3V=6(2V+4)-(V+5)

We move all terms to the left:

-2+3V-(6(2V+4)-(V+5))=0



We calculate terms in parentheses: -(6(2V+4)-(V+5)), so:

6(2V+4)-(V+5)

We multiply parentheses

12V-(V+5)+24

We get rid of parentheses

12V-V-5+24

We add all the numbers together, and all the variables

11V+19

Back to the equation:

-(11V+19)



We get rid of parentheses

3V-11V-19-2=0

We add all the numbers together, and all the variables

-8V-21=0

We move all terms containing V to the left, all other terms to the right

-8V=21

V=21/-8

V=-2+5/8

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