V-2=6v-4/8v=8v

Solution for V-2=6v-4/8v=8v equation:

-2=6V-4/8V=8V

We move all terms to the left:

-2-(6V-4/8V)=0


Domain of the equation: 8V)!=0

V!=0/1

V!=0

V∈R


We add all the numbers together, and all the variables

-(+6V-4/8V)-2=0

We get rid of parentheses

-6V+4/8V-2=0

We multiply all the terms by the denominator


-6V*8V-2*8V+4=0

Wy multiply elements

-48V^2-16V+4=0

a = -48; b = -16; c = +4;
Δ = b2-4ac
Δ = -162-4·(-48)·4
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-32}{2*-48}=\frac{-16}{-96}
=1/6
$
$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+32}{2*-48}=\frac{48}{-96}
=-1/2
$