W(2W-5)(3W+4)=520C

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Solution for W(2W-5)(3W+4)=520C equation: 


Simplifying
W(2W + -5)(3W + 4) = 520C

Reorder the terms:
W(-5 + 2W)(3W + 4) = 520C

Reorder the terms:
W(-5 + 2W)(4 + 3W) = 520C

Multiply (-5 + 2W) * (4 + 3W)
W(-5(4 + 3W) + 2W * (4 + 3W)) = 520C
W((4 * -5 + 3W * -5) + 2W * (4 + 3W)) = 520C
W((-20 + -15W) + 2W * (4 + 3W)) = 520C
W(-20 + -15W + (4 * 2W + 3W * 2W)) = 520C
W(-20 + -15W + (8W + 6W2)) = 520C

Combine like terms: -15W + 8W = -7W
W(-20 + -7W + 6W2) = 520C
(-20 * W + -7W * W + 6W2 * W) = 520C
(-20W + -7W2 + 6W3) = 520C

Solving
-20W + -7W2 + 6W3 = 520C

Solving for variable 'W'.

Reorder the terms:
-520C + -20W + -7W2 + 6W3 = 520C + -520C

Combine like terms: 520C + -520C = 0
-520C + -20W + -7W2 + 6W3 = 0

The solution to this equation could not be determined.

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