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(W)=-2-1/3W
We move all terms to the left:
(W)-(-2-1/3W)=0
Domain of the equation: 3W)!=0We add all the numbers together, and all the variables
W!=0/1
W!=0
W∈R
W-(-1/3W-2)=0
We get rid of parentheses
W+1/3W+2=0
We multiply all the terms by the denominator
W*3W+2*3W+1=0
Wy multiply elements
3W^2+6W+1=0
a = 3; b = 6; c = +1;
Δ = b2-4ac
Δ = 62-4·3·1
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$W_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$W_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$$W_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{6}}{2*3}=\frac{-6-2\sqrt{6}}{6} $$W_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{6}}{2*3}=\frac{-6+2\sqrt{6}}{6} $
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