W+70=(4w)2

Solution for W+70=(4w)2 equation:

+70=(4W)2

We move all terms to the left:

+70-((4W)2)=0

determiningTheFunctionDomain
-4W2+70=0

We add all the numbers together, and all the variables

-4W^2+70=0

a = -4; b = 0; c = +70;
Δ = b2-4ac
Δ = 02-4·(-4)·70
Δ = 1120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$W_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$W_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1120}=\sqrt{16*70}=\sqrt{16}*\sqrt{70}=4\sqrt{70}$
$W_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{70}}{2*-4}=\frac{0-4\sqrt{70}}{-8}
=-\frac{4\sqrt{70}}{-8}
=-\frac{\sqrt{70}}{-2}
$
$W_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{70}}{2*-4}=\frac{0+4\sqrt{70}}{-8}
=\frac{4\sqrt{70}}{-8}
=\frac{\sqrt{70}}{-2}
$