W-7=4(1/5w+3)-28

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Solution for W-7=4(1/5w+3)-28 equation: 



-7=4(1/5W+3)-28

We move all terms to the left:

-7-(4(1/5W+3)-28)=0



Domain of the equation: 5W+3)-28)!=0

W∈R



We multiply all the terms by the denominator


-(4(1-7*5W+3)-28)=0



We calculate terms in parentheses: -(4(1-7*5W+3)-28), so:

4(1-7*5W+3)-28

We add all the numbers together, and all the variables

4(-7*5W+4)-28

We multiply parentheses

-140W+16-28

We add all the numbers together, and all the variables

-140W-12

Back to the equation:

-(-140W-12)



We get rid of parentheses

140W+12=0

We move all terms containing W to the left, all other terms to the right

140W=-12

W=-12/140

W=-3/35

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