W=(r1+r2)

Solution for W=(r1+r2) equation:

=(W1+W2)

We move all terms to the left:

-((W1+W2))=0

We add all the numbers together, and all the variables

-((+W+W^2))=0


We calculate terms in parentheses: -((+W+W^2)), so:

(+W+W^2)

We get rid of parentheses

W^2+W

Back to the equation:

-(W^2+W)


We get rid of parentheses

-W^2-W=0

We add all the numbers together, and all the variables

-1W^2-1W=0

a = -1; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-1)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$W_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$W_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$W_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-1}=\frac{0}{-2}
=0
$
$W_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-1}=\frac{2}{-2}
=-1
$