X((1/5)x)=9/20

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Solution for X((1/5)x)=9/20 equation: 



X((1/5)X)=9/20

We move all terms to the left:

X((1/5)X)-(9/20)=0



Domain of the equation: 5)X)!=0

X!=0/1

X!=0

X∈R



We add all the numbers together, and all the variables

X((+1/5)X)-(+9/20)=0

We get rid of parentheses

X((+1/5)X)-9/20=0

We calculate fractions


(X((+1*20)/5X)*20)+(-45X)/5X)*20)=0



We calculate terms in parentheses: +(X((+1*20)/5X)*20), so:

X((+1*20)/5X)*20

We add all the numbers together, and all the variables

X(20/5X)*20

We multiply parentheses

400X^2

Back to the equation:

+(400X^2)



We get rid of parentheses

400X^2-45X)/5X)*20=0

We multiply all the terms by the denominator


400X^2*5X)*20-45X)=0

Wy multiply elements

40000X^4=0

We do not support eXpression: X^4

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