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X(-10+4X)=180
We move all terms to the left:
X(-10+4X)-(180)=0
We add all the numbers together, and all the variables
X(4X-10)-180=0
We multiply parentheses
4X^2-10X-180=0
a = 4; b = -10; c = -180;
Δ = b2-4ac
Δ = -102-4·4·(-180)
Δ = 2980
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2980}=\sqrt{4*745}=\sqrt{4}*\sqrt{745}=2\sqrt{745}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{745}}{2*4}=\frac{10-2\sqrt{745}}{8} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{745}}{2*4}=\frac{10+2\sqrt{745}}{8} $
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