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X(-3X)+2(-3X)=0
We multiply parentheses
-3X^2-6X=0
a = -3; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·(-3)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*-3}=\frac{0}{-6} =0 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*-3}=\frac{12}{-6} =-2 $
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