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X(15X-8)=0
We multiply parentheses
15X^2-8X=0
a = 15; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·15·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*15}=\frac{0}{30} =0 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*15}=\frac{16}{30} =8/15 $
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