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X(16+8X)=0
We add all the numbers together, and all the variables
X(8X+16)=0
We multiply parentheses
8X^2+16X=0
a = 8; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·8·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*8}=\frac{-32}{16} =-2 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*8}=\frac{0}{16} =0 $
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