X(2-x)=5(x+2)-4

Solution for X(2-x)=5(x+2)-4 equation:

X(2-X)=5(X+2)-4

We move all terms to the left:

X(2-X)-(5(X+2)-4)=0

We add all the numbers together, and all the variables

X(-1X+2)-(5(X+2)-4)=0

We multiply parentheses

-1X^2+2X-(5(X+2)-4)=0


We calculate terms in parentheses: -(5(X+2)-4), so:

5(X+2)-4

We multiply parentheses

5X+10-4

We add all the numbers together, and all the variables

5X+6

Back to the equation:

-(5X+6)


We get rid of parentheses

-1X^2+2X-5X-6=0

We add all the numbers together, and all the variables

-1X^2-3X-6=0

a = -1; b = -3; c = -6;
Δ = b2-4ac
Δ = -32-4·(-1)·(-6)
Δ = -15
Delta is less than zero, so there is no solution for the equation