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X(2X+3)=230
We move all terms to the left:
X(2X+3)-(230)=0
We multiply parentheses
2X^2+3X-230=0
a = 2; b = 3; c = -230;
Δ = b2-4ac
Δ = 32-4·2·(-230)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-43}{2*2}=\frac{-46}{4} =-11+1/2 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+43}{2*2}=\frac{40}{4} =10 $
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