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X(2X+5)=663
We move all terms to the left:
X(2X+5)-(663)=0
We multiply parentheses
2X^2+5X-663=0
a = 2; b = 5; c = -663;
Δ = b2-4ac
Δ = 52-4·2·(-663)
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5329}=73$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-73}{2*2}=\frac{-78}{4} =-19+1/2 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+73}{2*2}=\frac{68}{4} =17 $
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