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X(2X+7)=44
We move all terms to the left:
X(2X+7)-(44)=0
We multiply parentheses
2X^2+7X-44=0
a = 2; b = 7; c = -44;
Δ = b2-4ac
Δ = 72-4·2·(-44)
Δ = 401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{401}}{2*2}=\frac{-7-\sqrt{401}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{401}}{2*2}=\frac{-7+\sqrt{401}}{4} $
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