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X(2X-4)=126
We move all terms to the left:
X(2X-4)-(126)=0
We multiply parentheses
2X^2-4X-126=0
a = 2; b = -4; c = -126;
Δ = b2-4ac
Δ = -42-4·2·(-126)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-32}{2*2}=\frac{-28}{4} =-7 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+32}{2*2}=\frac{36}{4} =9 $
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