X(2x-5)=(2x+5)(x-4)

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Solution for X(2x-5)=(2x+5)(x-4) equation: 



X(2X-5)=(2X+5)(X-4)

We move all terms to the left:

X(2X-5)-((2X+5)(X-4))=0

We multiply parentheses

2X^2-5X-((2X+5)(X-4))=0

We multiply parentheses ..

2X^2-((+2X^2-8X+5X-20))-5X=0



We calculate terms in parentheses: -((+2X^2-8X+5X-20)), so:

(+2X^2-8X+5X-20)

We get rid of parentheses

2X^2-8X+5X-20

We add all the numbers together, and all the variables

2X^2-3X-20

Back to the equation:

-(2X^2-3X-20)



We add all the numbers together, and all the variables

2X^2-5X-(2X^2-3X-20)=0

We get rid of parentheses

2X^2-2X^2-5X+3X+20=0

We add all the numbers together, and all the variables

-2X+20=0

We move all terms containing X to the left, all other terms to the right

-2X=-20

X=-20/-2

X=+10

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