X(3x+1)-4(x+2)=6+3x(x-2)

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Solution for X(3x+1)-4(x+2)=6+3x(x-2) equation:



X(3X+1)-4(X+2)=6+3X(X-2)
We move all terms to the left:
X(3X+1)-4(X+2)-(6+3X(X-2))=0
We multiply parentheses
3X^2+X-4X-(6+3X(X-2))-8=0
We calculate terms in parentheses: -(6+3X(X-2)), so:
6+3X(X-2)
determiningTheFunctionDomain 3X(X-2)+6
We multiply parentheses
3X^2-6X+6
Back to the equation:
-(3X^2-6X+6)
We add all the numbers together, and all the variables
3X^2-3X-(3X^2-6X+6)-8=0
We get rid of parentheses
3X^2-3X^2-3X+6X-6-8=0
We add all the numbers together, and all the variables
3X-14=0
We move all terms containing X to the left, all other terms to the right
3X=14
X=14/3
X=4+2/3

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