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X(3X+1)=310
We move all terms to the left:
X(3X+1)-(310)=0
We multiply parentheses
3X^2+X-310=0
a = 3; b = 1; c = -310;
Δ = b2-4ac
Δ = 12-4·3·(-310)
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3721}=61$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-61}{2*3}=\frac{-62}{6} =-10+1/3 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+61}{2*3}=\frac{60}{6} =10 $
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