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X(3X+3)=6(2+X/2)
We move all terms to the left:
X(3X+3)-(6(2+X/2))=0
We add all the numbers together, and all the variables
X(3X+3)-(6(X/2+2))=0
We multiply parentheses
3X^2+3X-(6(X/2+2))=0
We multiply all the terms by the denominator
3X^2*2+2))+3X*2+2))-(6(X=0
Wy multiply elements
6X^2+2))+3X*2+2))-(6(X=0
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